Age Word Problems

Age word problems involve finding the age of one or more individuals at a given point in time, based on the information provided in the problem.

Table of Contents:

• Age Word Problems
• Solved Examples
• Frequently Asked Questions

Age Word Problems

Here are some examples of age word problems:

There are no specific formulas for age word problems. However, there are some general steps that can be followed to solve age word problems:

Step 1: Read the problem carefully and identify the unknowns. Usually, the problem will ask for the age of one or more individuals at a specific point in time.

Step 2: Assign variables to represent the unknowns. Let’s say, for example, that the problem asks for the age of person A at a specific point in time. Then we can assign the variable A to represent that age.

Step 3: Use the information provided in the problem to set up one or more equations that relate the unknowns to each other.

Step 4: Solve the equations to find the values of the unknowns.

Step 5: Check your answer by making sure it satisfies all the conditions given in the problem.

It is important to note that age word problems can vary in complexity and may require additional steps or mathematical concepts to solve.

Solved Examples

Example 1 :

Lisa is 20 years older than Tom. In 5 years, Lisa’s age will be twice Tom’s age. How old is Tom now?
Solution: Let’s assume Tom’s current age is x. Then Lisa’s current age is x+20. In 5 years, Tom’s age will be x+5 and Lisa’s age will be x+25. According to the problem, Lisa’s age in 5 years will be twice Tom’s age in 5 years. So we can write an equation: x+25 = 2(x+5). Solving this equation, we get x=15. Therefore, Tom is currently 15 years old.

Example 2:

John is twice as old as Mary was when John was as old as Mary is now. If Mary is 20 years old, how old is John?
Solution:Let’s say:
Mary’s current age = M
John’s current age = J

According to the information given, John is twice as old as Mary was when John was as old as Mary is now. This means that the age difference between John and Mary remains constant.

Let’s say x represents the number of years ago when John was as old as Mary is now. At that time, John’s age was (J – x), and Mary’s age was (M – x).

We are given that Mary is currently 20 years old, so M = 20.

From the information above, we can create the following equation:
J = 2(M – x)

Now let’s substitute M with 20 in the equation:
J = 2(20 – x)

Since John’s current age is J and Mary’s current age is M, we know that J = M. Substituting J with M in the equation, we have:
M = 2(20 – x)

Since we know that M = 20, we can solve for x:
20 = 2(20 – x)
20 = 40 – 2x
2x = 40 – 20
2x = 20
x = 10

Now that we have x = 10, we can find John’s current age by substituting x back into the equation J = 2(20 – x):
J = 2(20 – 10)
J = 2(10)
J = 20

Therefore, John is currently 20 years old.

Example 3:

Alex is 5 years older than Bob, and Carol is twice as old as Alex. The sum of their ages is 66. How old is Bob?
Solution: Let’s assume Bob’s current age is x. Then Alex’s current age is x+5, and Carol’s present age is 2(x+5)=2x+10. According to the problem, the sum of their ages is 66. So we can write an equation: x+(x+5)+(2x+10)=66. Solving this equation, we get x=12.75. Therefore, Bob is currently 12.75 years old.

Example 4:

Jane is 10 years younger than John. In 5 years, Jane’s age will be half of John’s age. How old is John now?
Solution: Let’s assume John’s current age is x. Then Jane’s current age is x-10. In 5 years, John’s age will be (x+5)
Jane’s age will be (x-10)+5
Jane’s age will be x+5
According to the problem, Jane’s age will be age on 5 years will half John’s age,
x-5 = 1/2 (x+5)
2(x-5) = (x+5)
2x-10 = x+5
2x -x = 10 + 5
x = 15
John’s age will be 25 years.

Age Word Problems FAQS

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